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F a C Ro
t
Theorem
R
e
M
a
i
N
d
e
R
THEOREM
REMAINDER THEOREM: If
the polynomial P(X) is
divided by X-C, then
the remainder is P(C).
FACTOR THEOREM: If the
remainder comes out to
be 0 (zero), then X-C
is a factor of P(X).
E SM
a
x L
p e
f(x)= x4 – 13x2 + 36
𝑝
𝑞
=
±1,±2,±3,±4,±6,±9,±12,±18,±36
±1
Possible roots:
±1, ±2, ±3, ±4, ±6, ±9, ±12,
±18, ±36
1.
If x= 1:
f(1) = (1)4 – 13(1)2 + 36
= 1 – 13(1) + 36
= 1 – 13 + 36
= 24
Therefore, x=1 is not a root and
(x-1) is not a factor.
If x= -1:
f(-1) = (-1)4 – 13(-1)2 + 36
= 1 – 13(1) + 36
= 1 – 13 + 36
= 24
Therefore, x=-1 is not a root and
(x+1) is not a factor.
If x= 2:
f(2) = (2)4 – 13(2)2 + 36
= 16 – 13(4) + 36
= 16 – 52 + 36
= 0
Therefore, x=2 is a root and (x-2)
is a factor.
If x= -2:
f(-2) = (-2)4 – 13(-2)2 + 36
= 16 – 13(4) + 36
= 16 – 52 + 36
= 0
Therefore, x=-2 is a root and
(x+2) is a factor.
If x= 3:
f(3) = (3)4 – 13(3)2 + 36
= 81 – 13(9) + 36
= 81 – 117 + 36
= 0
Therefore, x=3 is a root and
(x-3) is a factor.
If x= -3:
f(-3) = (-3)4 – 13(-3)2 + 36
= 81 – 13(9) + 36
= 81 – 117 + 36
= 0
Therefore, x=3 is a root and
(x-3) is a factor.
Since the exponent of the
polynomial function is 4,
there should be four roots
and four factors.
The roots of the polynomial
function, f(x) = x4 – 13x2
+ 36, are ± 2 𝑎𝑛𝑑 ± 3 . The
factors of the polynomial
function are (x-2) (x+2)
(x-3) (x+3).
f(x) = x2– 12x + 9
𝑝
𝑞
=
±1,±3,±9,
±1
if x = 1
= 12- 10(1) + 9
= 1 -10 + 9
=0
Therefore, x=1 is a root and
(x-1) is a factor.
2.
If x = -1
= 12- 10(-1) + 9
= 1 +10 + 9
=20
Therefore, x=-1 is a not a
root and (x+1) is not a
factor.
if x = 3
= 32- 10(3) + 9
= 9 - 30 + 9
= -2
Therefore, x=3 is a not root
and (x-3) is not a factor.
if x = -3
= -32- 10(-3) + 9
= 9 + 30 + 9
= 48
Therefore, x=-3 is not a root
and (x+3) is a not factor.
if x = 9
= 92- 10(9) + 9
= 81 -90 + 9
= 0
Therefore, x=9 is a root and
(x-9) is a factor.
If x =- 9
= 92- 10(9) + 9
= -81 + 90 + 9
= 18
Therefore, x=-9 is not a root
and (x+9) is not a factor.
Since the exponent of the polynomial
function is 2, there should be two
roots and two factors.
The roots of the polynomial function,
f(x) = x2– 12x + 9 ate
+1 𝑎𝑛𝑑 + 9. The factors of the
polynomial function are (x-1) (x-9)
Danielle Erika L.
Diva
Ronalie C. Mejos
Mark Lenon F. Dacir
Rafael C. Vallejos
MEMBERS
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Factor Theorem and Remainder Theorem

  • 1. F a C Ro t Theorem R e M a i N d e R THEOREM
  • 2. REMAINDER THEOREM: If the polynomial P(X) is divided by X-C, then the remainder is P(C). FACTOR THEOREM: If the remainder comes out to be 0 (zero), then X-C is a factor of P(X).
  • 4. f(x)= x4 – 13x2 + 36 𝑝 𝑞 = ±1,±2,±3,±4,±6,±9,±12,±18,±36 ±1 Possible roots: ±1, ±2, ±3, ±4, ±6, ±9, ±12, ±18, ±36 1.
  • 5. If x= 1: f(1) = (1)4 – 13(1)2 + 36 = 1 – 13(1) + 36 = 1 – 13 + 36 = 24 Therefore, x=1 is not a root and (x-1) is not a factor. If x= -1: f(-1) = (-1)4 – 13(-1)2 + 36 = 1 – 13(1) + 36 = 1 – 13 + 36 = 24 Therefore, x=-1 is not a root and (x+1) is not a factor.
  • 6. If x= 2: f(2) = (2)4 – 13(2)2 + 36 = 16 – 13(4) + 36 = 16 – 52 + 36 = 0 Therefore, x=2 is a root and (x-2) is a factor. If x= -2: f(-2) = (-2)4 – 13(-2)2 + 36 = 16 – 13(4) + 36 = 16 – 52 + 36 = 0 Therefore, x=-2 is a root and (x+2) is a factor.
  • 7. If x= 3: f(3) = (3)4 – 13(3)2 + 36 = 81 – 13(9) + 36 = 81 – 117 + 36 = 0 Therefore, x=3 is a root and (x-3) is a factor. If x= -3: f(-3) = (-3)4 – 13(-3)2 + 36 = 81 – 13(9) + 36 = 81 – 117 + 36 = 0 Therefore, x=3 is a root and (x-3) is a factor.
  • 8. Since the exponent of the polynomial function is 4, there should be four roots and four factors. The roots of the polynomial function, f(x) = x4 – 13x2 + 36, are ± 2 𝑎𝑛𝑑 ± 3 . The factors of the polynomial function are (x-2) (x+2) (x-3) (x+3).
  • 9. f(x) = x2– 12x + 9 𝑝 𝑞 = ±1,±3,±9, ±1 if x = 1 = 12- 10(1) + 9 = 1 -10 + 9 =0 Therefore, x=1 is a root and (x-1) is a factor. 2.
  • 10. If x = -1 = 12- 10(-1) + 9 = 1 +10 + 9 =20 Therefore, x=-1 is a not a root and (x+1) is not a factor. if x = 3 = 32- 10(3) + 9 = 9 - 30 + 9 = -2 Therefore, x=3 is a not root and (x-3) is not a factor.
  • 11. if x = -3 = -32- 10(-3) + 9 = 9 + 30 + 9 = 48 Therefore, x=-3 is not a root and (x+3) is a not factor. if x = 9 = 92- 10(9) + 9 = 81 -90 + 9 = 0 Therefore, x=9 is a root and (x-9) is a factor.
  • 12. If x =- 9 = 92- 10(9) + 9 = -81 + 90 + 9 = 18 Therefore, x=-9 is not a root and (x+9) is not a factor. Since the exponent of the polynomial function is 2, there should be two roots and two factors. The roots of the polynomial function, f(x) = x2– 12x + 9 ate +1 𝑎𝑛𝑑 + 9. The factors of the polynomial function are (x-1) (x-9)
  • 13. Danielle Erika L. Diva Ronalie C. Mejos Mark Lenon F. Dacir Rafael C. Vallejos MEMBERS X- Einstein