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Capacitors 
Storage of charge
Introduction 
• Read Chapter 14 in ESA and then; 
– Write a brief description of what a capacitor is 
and what it does, make sure you mention 
dielectric 
– Describe the maths; capacitance, units, 
capacitor formula 
– Explain how capacitors behave in DC circuits 
in series and parallel
Electronic Components 
• Capacitors are 
electronic components 
that store charge 
efficiently 
• They can be charged 
and discharged very 
quickly and hold their 
charge indefinitely 
• Symbol
The structure of the capacitor 
• Capacitors are made 
from two parallel 
metal plates 
separated by an 
insulator called a 
dielectric 
• In practice they 
appear a little more 
complex
Charging a Capacitor 
• In a circuit the capacitor 
plate closest to the 
negative terminal of the 
battery or power supply is 
“stacked” with electrons 
(negative charges) 
• The opposite plate 
becomes positively 
charged 
• There is no movement of 
charge between the 
plates as they are 
insulated by the dielectric
Capacitance (symbol C) 
• Capacitance is the amount of charge a capacitor can 
store when connected across a potential difference of 
1V (the larger the capacitance the more charge it can store) 
Q 
• Units of capacitance are Farads (symbol F) 
• 1 Farad = 1 coulomb per volt This is a lot of charge!! 
• most capacitors are small; 
μF (1 x 10-6 F) 
nF (1 x 10-9 F) 
pF (1 x 10-12 F) 
V 
C  
Where; 
C=Capacitance in Farads (F) 
Q=Charge in Coulombs (C) 
V=Voltage in Volts(V)
Exercises 
1. Calculate the capacitance of a capacitor 
that stores 1.584  10-9 C at 7.2V 
220 μF 
2. A 330μF capacitor is charged by a 9.0V 
battery. How much charge will it store? 
2.97  10-3 C 
3. A 0.1μF capacitor stores 1.5  10-7 C of 
the charge. What was the voltage used to 
charge it? 
1.5V
Capacitance (C) 
Three factors determine 
capacitance; 
1. The area of the plates 
(CA) 
2. The distance separating 
the plates 
1 
(C  ) 
d 
3. The properties of the 
dielectric (εr) 
so 
C= constant x 
A 
d
Capacitor Construction Formula 
• If there is air or a vacuum between the plates the 
constant is; 
the absolute permittivity of free space (symbol ε0) 
(ε0 = 8.84 x 10-12 Fm-1) 
so; 
A 
C 0  
 
d
Exercises 
C 0  
Using the absolute permittivity of free space 
(ε0 = 8.84  10-12 Fm-1) 
A 
1. Calculate the capacitance of a capacitor that has 
a plate separation of 15 microns (μm) and 
measures 45cm by 28cm. 
74nF 
2. A 1000 μF has an area of 2cm by 4.8m. What is 
the distance between the plates in mm? 
8.48  10-7mm 
3. A 0.3 μF capacitor with a plate separation of 2 
microns. What is the area of the capacitor? 
0.68m2 
d 

Capacitor Construction Formula 
• When an insulator (dielectric) is placed between 
the plates the capacitance increases 
• The dielectric constant (symbol εr) gives the 
proportion by which the capacitance will increase 
so; 
and therefore 
dielectic r air C  C 
C r o   
 
d 
A 
Note that εr has no units as 
dielectric 
air 
C 
  
r C 
Insulator εr 
Air 1 
Polystyrene 2.5 
Glass 6.0 
Water 80
The Role of the Dielectric 
• Charge separation in a 
parallel-plate capacitor 
causes an internal 
electric field. A 
dielectric (orange) 
increases the field 
strength and increases 
the capacitance
Examples 
1. Calculate the capacitance of a capacitor with a 
polystyrene dielectric (εr =2.5), an area of 1.2cm by 
3.2m and a plate separation of 8 microns 
1.06  10-7 F 
2. Calculate the plate area required for a 1000 μF, glass 
(εr=6.0) capacitor, with a plate separation of 2.8 
micrometres. 
53m2 
3. Calculate the dielectic constant of a 10000 μF 
capacitor with a 1.2μm plate separation and an area 
of 16.97m2 
80 
d 
A 
C r o   
 (ε0 = 8.84 x 10-12 Fm- 
1)
Networks of Capacitors 
Capacitors in Parallel 
• For two or more 
capacitors in parallel the 
capacitance is 
1 2... C C C parallel   
• Each capacitor has the 
same voltage 
charging it so; 
The more capacitors in parallel circuit the greater 
the capacitance of the circuit
Capacitors in Series 
• Capacitors share the supply 
voltage 
• The inner plates are an 
isolated circuit where the 
existing charges are just 
rearranged 
so; 
... 
1 1 1 
  
1 2 C C C series 
The more capacitors in series the less the total 
capacitance of the circuit
Examples 
1. A circuit has three 330 μF capacitors in 
series. Calculate the total capacitance of the 
circuit 110 μF 
2. Another circuit has three 330 μF capacitors 
in parallel. Calculate the total capacitance of 
the circuit. 990 μF 
3. Briefly explain why these two circuits have a 
different total capacitance. 
The parallel capacitors are each charged 
separately while the series capacitors charge 
through one another, effectively just 
rearranging the charges within each capacitor 
(the electric field is weakened by the addition 
of each capacitor in series)
Energy Stored in Capacitors 
• The graph of voltage 
against charge for a cell is 
a horizontal line 
– The energy provided by 
the cell is equal to the 
area under the line 
• The graph of voltage 
against charge is a straight 
line through (0, 0) 
– The energy stored in a 
capacitor is; 
1 
 
E QV P 
2 
Q 
V 
Energy Produced by a Cell 
Energy Stored by a Capacitor 
Q 
V
Energy Stored in Capacitors 
1 
 
• Energy of a capacitor can also be given by; 
(because Q=CV) 
or 
Q 
(because ) 
E QV P 
2 
1 
 
2 E CV P 
2 
Q 
C 
EP 
2 
1 
 
2 
C 
V  
Energy is stored as electrical charge on the plates of a 
capacitor
Exercises 
1 
 
E CV 2 P 
1. Calculate the energy stored in a 330μF 
capacitor charged by a 24V supply. 
0.095J 
2. Calculate the capacitance of a capacitor 
that stores 1.8  10-3 J of energy at 18V 
11 μF 
3. Calculate the voltage require to store 0.1J 
of energy on a 1000μF capacitor 
200V 
2
Charging and Discharging Capacitors 
1. Charging a Capacitor 
• As a capacitor charges 
the voltage increases to 
the supply voltage 
(exponential growth curve) 
• and the current 
decreases as the plates 
become “full” of charge 
(exponential decay curve) 
Current 
Time 
Voltage 
Supply voltage 
Time 
The shape of these curves can be controlled by a resistor in series, the 
higher the resistance the slower the charge
Charging and Discharging Capacitors 
2. Discharging a Capacitor 
• The voltage across the 
plates of the capacitor 
drops as the charges flow 
away from the plate 
• The current decreases as 
there are fewer charges on 
the plates repelling each 
other 
Current 
Time 
Voltage 
Time 
The shape of these curves can be controlled by a resistor in series, the 
higher the resistance the slower the discharge
Time Constant (  
) 
 
• The time constant ( )is a measure of how 
quickly a capacitor charges or discharges 
– This will depend on: 
• The resistance (R) of the circuit (how much current 
flows) 
• The capacitance (C) of the capacitor (how much 
charge is stored) 
so: 
  RC 
NB; one time constant is not the total time to charge or 
discharge but the time to discharge to 37.5% or to charge to 
63.5% of the total
Time Constant ( ) 
• One time constant is not the total 
time to charge or discharge but the 
time to discharge to 37.5% or to 
charge to 63.5% of the total 
• Experts; this is because of the 
exponential nature of the 
charge/discharge curves 
 
V 
RC t 
63.5 
% 
V 
t 
RC 
37. 
5% 
C 
For Decay V  
V e 
when t V V e 
1 
1 
C 
t 
C 
  
 
as e  
 0.37, V  0.37  
V 
 
 
 , 
, ( ) 
C 
For growth V  V 1  
e 
when t V V 1 e 
1 
1 
   
C 
t 
C 
as e  
 0.37, V  0.63  
V 
 
 
( ) 
 

Examples 
1. Calculate the time constant for 330μF 
capacitor in a 20 charging circuit 
6.6  10-3s 
2. Calculate the time constant for 330μF 
capacitor in a 15 discharging circuit 
5.0  10-3s 
3. Calculate the amount of charge on each 
of the capacitors in 1 and 2 after 1 time 
constant when charged from 12V supply. 
1 = 2.5  10-3C, 2=1.5  10-3C
Exercises 
• Try ESA, Activity 14A,B,C, Pg 224 
• ABA, Pg 139-153

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Capacitors

  • 2. Introduction • Read Chapter 14 in ESA and then; – Write a brief description of what a capacitor is and what it does, make sure you mention dielectric – Describe the maths; capacitance, units, capacitor formula – Explain how capacitors behave in DC circuits in series and parallel
  • 3. Electronic Components • Capacitors are electronic components that store charge efficiently • They can be charged and discharged very quickly and hold their charge indefinitely • Symbol
  • 4. The structure of the capacitor • Capacitors are made from two parallel metal plates separated by an insulator called a dielectric • In practice they appear a little more complex
  • 5. Charging a Capacitor • In a circuit the capacitor plate closest to the negative terminal of the battery or power supply is “stacked” with electrons (negative charges) • The opposite plate becomes positively charged • There is no movement of charge between the plates as they are insulated by the dielectric
  • 6. Capacitance (symbol C) • Capacitance is the amount of charge a capacitor can store when connected across a potential difference of 1V (the larger the capacitance the more charge it can store) Q • Units of capacitance are Farads (symbol F) • 1 Farad = 1 coulomb per volt This is a lot of charge!! • most capacitors are small; μF (1 x 10-6 F) nF (1 x 10-9 F) pF (1 x 10-12 F) V C  Where; C=Capacitance in Farads (F) Q=Charge in Coulombs (C) V=Voltage in Volts(V)
  • 7. Exercises 1. Calculate the capacitance of a capacitor that stores 1.584  10-9 C at 7.2V 220 μF 2. A 330μF capacitor is charged by a 9.0V battery. How much charge will it store? 2.97  10-3 C 3. A 0.1μF capacitor stores 1.5  10-7 C of the charge. What was the voltage used to charge it? 1.5V
  • 8. Capacitance (C) Three factors determine capacitance; 1. The area of the plates (CA) 2. The distance separating the plates 1 (C  ) d 3. The properties of the dielectric (εr) so C= constant x A d
  • 9. Capacitor Construction Formula • If there is air or a vacuum between the plates the constant is; the absolute permittivity of free space (symbol ε0) (ε0 = 8.84 x 10-12 Fm-1) so; A C 0   d
  • 10. Exercises C 0  Using the absolute permittivity of free space (ε0 = 8.84  10-12 Fm-1) A 1. Calculate the capacitance of a capacitor that has a plate separation of 15 microns (μm) and measures 45cm by 28cm. 74nF 2. A 1000 μF has an area of 2cm by 4.8m. What is the distance between the plates in mm? 8.48  10-7mm 3. A 0.3 μF capacitor with a plate separation of 2 microns. What is the area of the capacitor? 0.68m2 d 
  • 11. Capacitor Construction Formula • When an insulator (dielectric) is placed between the plates the capacitance increases • The dielectric constant (symbol εr) gives the proportion by which the capacitance will increase so; and therefore dielectic r air C  C C r o    d A Note that εr has no units as dielectric air C   r C Insulator εr Air 1 Polystyrene 2.5 Glass 6.0 Water 80
  • 12. The Role of the Dielectric • Charge separation in a parallel-plate capacitor causes an internal electric field. A dielectric (orange) increases the field strength and increases the capacitance
  • 13. Examples 1. Calculate the capacitance of a capacitor with a polystyrene dielectric (εr =2.5), an area of 1.2cm by 3.2m and a plate separation of 8 microns 1.06  10-7 F 2. Calculate the plate area required for a 1000 μF, glass (εr=6.0) capacitor, with a plate separation of 2.8 micrometres. 53m2 3. Calculate the dielectic constant of a 10000 μF capacitor with a 1.2μm plate separation and an area of 16.97m2 80 d A C r o    (ε0 = 8.84 x 10-12 Fm- 1)
  • 14. Networks of Capacitors Capacitors in Parallel • For two or more capacitors in parallel the capacitance is 1 2... C C C parallel   • Each capacitor has the same voltage charging it so; The more capacitors in parallel circuit the greater the capacitance of the circuit
  • 15. Capacitors in Series • Capacitors share the supply voltage • The inner plates are an isolated circuit where the existing charges are just rearranged so; ... 1 1 1   1 2 C C C series The more capacitors in series the less the total capacitance of the circuit
  • 16. Examples 1. A circuit has three 330 μF capacitors in series. Calculate the total capacitance of the circuit 110 μF 2. Another circuit has three 330 μF capacitors in parallel. Calculate the total capacitance of the circuit. 990 μF 3. Briefly explain why these two circuits have a different total capacitance. The parallel capacitors are each charged separately while the series capacitors charge through one another, effectively just rearranging the charges within each capacitor (the electric field is weakened by the addition of each capacitor in series)
  • 17. Energy Stored in Capacitors • The graph of voltage against charge for a cell is a horizontal line – The energy provided by the cell is equal to the area under the line • The graph of voltage against charge is a straight line through (0, 0) – The energy stored in a capacitor is; 1  E QV P 2 Q V Energy Produced by a Cell Energy Stored by a Capacitor Q V
  • 18. Energy Stored in Capacitors 1  • Energy of a capacitor can also be given by; (because Q=CV) or Q (because ) E QV P 2 1  2 E CV P 2 Q C EP 2 1  2 C V  Energy is stored as electrical charge on the plates of a capacitor
  • 19. Exercises 1  E CV 2 P 1. Calculate the energy stored in a 330μF capacitor charged by a 24V supply. 0.095J 2. Calculate the capacitance of a capacitor that stores 1.8  10-3 J of energy at 18V 11 μF 3. Calculate the voltage require to store 0.1J of energy on a 1000μF capacitor 200V 2
  • 20. Charging and Discharging Capacitors 1. Charging a Capacitor • As a capacitor charges the voltage increases to the supply voltage (exponential growth curve) • and the current decreases as the plates become “full” of charge (exponential decay curve) Current Time Voltage Supply voltage Time The shape of these curves can be controlled by a resistor in series, the higher the resistance the slower the charge
  • 21. Charging and Discharging Capacitors 2. Discharging a Capacitor • The voltage across the plates of the capacitor drops as the charges flow away from the plate • The current decreases as there are fewer charges on the plates repelling each other Current Time Voltage Time The shape of these curves can be controlled by a resistor in series, the higher the resistance the slower the discharge
  • 22. Time Constant (  )  • The time constant ( )is a measure of how quickly a capacitor charges or discharges – This will depend on: • The resistance (R) of the circuit (how much current flows) • The capacitance (C) of the capacitor (how much charge is stored) so:   RC NB; one time constant is not the total time to charge or discharge but the time to discharge to 37.5% or to charge to 63.5% of the total
  • 23. Time Constant ( ) • One time constant is not the total time to charge or discharge but the time to discharge to 37.5% or to charge to 63.5% of the total • Experts; this is because of the exponential nature of the charge/discharge curves  V RC t 63.5 % V t RC 37. 5% C For Decay V  V e when t V V e 1 1 C t C    as e   0.37, V  0.37  V    , , ( ) C For growth V  V 1  e when t V V 1 e 1 1    C t C as e   0.37, V  0.63  V   ( )  
  • 24. Examples 1. Calculate the time constant for 330μF capacitor in a 20 charging circuit 6.6  10-3s 2. Calculate the time constant for 330μF capacitor in a 15 discharging circuit 5.0  10-3s 3. Calculate the amount of charge on each of the capacitors in 1 and 2 after 1 time constant when charged from 12V supply. 1 = 2.5  10-3C, 2=1.5  10-3C
  • 25. Exercises • Try ESA, Activity 14A,B,C, Pg 224 • ABA, Pg 139-153