Brief comparison between Separate Wall Method and Center Line Method of estimation of buildings in Civil Engineering

1. Prepared by:-
Er. Simarpreet Singh
A.P, Civil Engg.
ACET, Amritsar

2. TABLE OF CONTENTS
 One Room Building
 Concrete work in foundation (Center line and
separate wall method)
 Brickwork in footing (Center line and separate wall
method)
 Brickwork in walls (Center line and separate wall
method)
 Two Rooms Building
 Concrete work in foundation (Center line and
separate wall method)

4. 5m
4m
0.3m
0.3m
0.5m
0.6m
0.9m
0.4m
0.6m
3.5m
Section at A-A’ and B-B’
Thickness of footing and foundation is 30 cm each
A
A’
B B’
Plan

5. 0.9 m
5.3m
4.3 m
Total Center line = 5.3+5.3+4.3+4.3=19.2 m
Width = 0.9 m Total Qty of concrete in foundation= (19.2×0.9×0.3) cum
Center Line Method

6. 0.9 m
5.3m
6.2m
4.3 m
3.4 m
Separate Wall Method
Width = 0.9 m Total Qty of concrete in fdn= (2×6.2×0.9×0.3) + (2×3.4×0.9×0.3)cum
Long Wall = 5.3+0.9=6.2 m Short Wall = 4.3-0.9=3.4 m

7. 0.6 m
5.3m
4.3 m
Total Center line = 5.3+5.3+4.3+4.3=19.2 m
Width = 0.6 m Total Qty of brickwork in Ist footing= (19.2×0.6×0.3) cum
Center Line Method

8. 0.6 m
5.3m
5.9 m
4.3 m
3.7 m
Width = 0.6 m
Separate Wall Method
Long Wall = 5.3+0.6=5.9 m Short Wall = 4.3-0.6=3.7 m
Total Qty of brickwork in Ist footing= (2×5.9×0.6×0.3) + (2×3.7×0.6×0.3)cum

9. 5.3m
4.3 m
0.3 m
Total Center line = 5.3+5.3+4.3+4.3=19.2 m
Width = 0.3 m Total Qty of brickwork in walls= (19.2×0.3×3.5) cum
Center Line Method

10. 5.6 m
5.3m
4.3 m
4 m
0.3 m
Width = 0.3 m
Separate Wall Method
Long Wall = 5.3+0.3=5.6 m Short Wall = 4.3-0.3=4.0 m
Total Qty of brickwork in walls= (2×5.6×0.3×3.5) + (2×4.0×0.3×3.5)cum

12. 5m
4m
0.3m
0.3m
0.5m
0.6m
0.9m
0.4m
0.6m
3.5m
Section at A-A’ and B-B’
Thickness of footing and foundation is 30 cm each
A
A’
B B’
Plan

13. Center Line Method
Total Center line = 5.3+5.3+5.3+5.3+4.3+4.3+4.3=34.1 m
Width = 0.9 m Total Qty of concrete in fdn= (34.1×0.9×0.3)
5.3m 5.3m
4.3 m
0.9 m
Intermediate wall
– (2×0.9×(0.9/2) ×0.3)cum

14. Separate Wall Method
Long Wall = 5.3+5.3+0.9=11.5 m Short Wall = 4.3-0.9=3.4 m
Width = 0.9 m Total Qty of concrete in fdn= (2×11.5×0.9×0.3)
5.3m 5.3m
4.3 m
0.9 m
11.5 m
3.4m
Intermediate wall
+ (3×3.4×0.9×0.3)cum